If 0.30 moles of solute are dissolved in 0.10 kilograms of solvent, what is the molality?

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Multiple Choice

If 0.30 moles of solute are dissolved in 0.10 kilograms of solvent, what is the molality?

Explanation:
Molality is the amount of solute per kilogram of solvent. Here, 0.30 moles of solute divided by 0.10 kilograms of solvent gives 0.30 / 0.10 = 3.0 mol/kg. This measure uses mass of solvent (in kilograms) rather than volume, so the value reflects concentration independent of density or temperature changes. The other numbers would come from a different amount of solvent; with the given 0.10 kg, the result is 3.0.

Molality is the amount of solute per kilogram of solvent. Here, 0.30 moles of solute divided by 0.10 kilograms of solvent gives 0.30 / 0.10 = 3.0 mol/kg. This measure uses mass of solvent (in kilograms) rather than volume, so the value reflects concentration independent of density or temperature changes. The other numbers would come from a different amount of solvent; with the given 0.10 kg, the result is 3.0.

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